(8x+3)(2x^2-5x-3)=0

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Solution for (8x+3)(2x^2-5x-3)=0 equation: 


Simplifying
(8x + 3)(2x2 + -5x + -3) = 0

Reorder the terms:
(3 + 8x)(2x2 + -5x + -3) = 0

Reorder the terms:
(3 + 8x)(-3 + -5x + 2x2) = 0

Multiply (3 + 8x) * (-3 + -5x + 2x2)
(3(-3 + -5x + 2x2) + 8x * (-3 + -5x + 2x2)) = 0
((-3 * 3 + -5x * 3 + 2x2 * 3) + 8x * (-3 + -5x + 2x2)) = 0
((-9 + -15x + 6x2) + 8x * (-3 + -5x + 2x2)) = 0
(-9 + -15x + 6x2 + (-3 * 8x + -5x * 8x + 2x2 * 8x)) = 0
(-9 + -15x + 6x2 + (-24x + -40x2 + 16x3)) = 0

Reorder the terms:
(-9 + -15x + -24x + 6x2 + -40x2 + 16x3) = 0

Combine like terms: -15x + -24x = -39x
(-9 + -39x + 6x2 + -40x2 + 16x3) = 0

Combine like terms: 6x2 + -40x2 = -34x2
(-9 + -39x + -34x2 + 16x3) = 0

Solving
-9 + -39x + -34x2 + 16x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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